3^x + 4^x = 5^x (Find x)

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This answer was edited.X = 2

use Newton Ralphson formula,

i.e X1-f(x)/f”(x)

x1=2 cos if substitue 2 into 3^x 4^x-5^x, we will av f(X) to be 0

f”(x)=3^xln3 4^xln4-5^xln5

f(x)=0

so 2-0/3^xln3 4^xln4-5^xln5 which is equal to 2.